How do you divide $(sqrt6+sqrt3)/ sqrt2$ ?

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Answer 1 · 2015-06-16T16:25:11

$sqrt(3)+sqrt(6)/2$

Separate the numerator using the common denominator of $sqrt(2)$

$sqrt(6)/sqrt(2)+sqrt(3)/sqrt(2)$

Write using single radicals, $sqrt()$

$sqrt(6/2)+sqrt(3)/sqrt(2)$

Simplify the first term

$sqrt(3)+sqrt(3)/sqrt(2)$

Rationalize the second term by multiplying the numerator and denominator by $sqrt(2)$

$sqrt(3)+sqrt(3)/sqrt(2)*sqrt(2)/sqrt(2)=sqrt(3)+sqrt(6)/2$

How do you divide (sqrt6+sqrt3)/ sqrt2(sqrt6+sqrt3)/ sqrt2?