How do you divide $(n^4+5n^3-6n+3)div(n+3)$ using synthetic division?

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How do you divide $(n^4+5n^3-6n+3)div(n+3)$ using synthetic division?

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Answer 1 · 2017-05-30T05:36:44

The remainder is $=-33$ and the quotient is $=n^3+2n^2-6n+12$

Explanation:

Let's perform the synthetic division

$color(white)(aaaa)$ $-3$ $color(white)(aaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaaa)$ $5$ $color(white)(aaaaaa)$ $0$ $color(white)(aaaaa)$ $-6$ $color(white)(aaaaaaa)$ $3$
$color(white)(aaaaaaaaaaaa)$ _________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $color(white)(aaaaaa)$ $-3$ $color(white)(aaaaaa)$ $-6$ $color(white)(aaaa)$ $18$ $color(white)(aaaaa)$ $-36$
$color(white)(aaaaaaaaaaaa)$ ________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaaaa)$ $2$ $color(white)(aaaaaa)$ $-6$ $color(white)(aaaa)$ $12$ $color(white)(aaaaa)$ $color(red)(-33)$

$(n^4+5n^3-6n+3)/(n+3)=(n^3+2n^2-6n+12)-33/(n+3)$

The remainder is $=-33$ and the quotient is $=n^3+2n^2-6n+12$

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How do you divide $(n^4+5n^3-6n+3)div(n+3)$ using synthetic division?

1 Answer

Explanation:

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How do you divide (n^4+5n^3-6n+3)div(n+3)(n^4+5n^3-6n+3)div(n+3) using synthetic division?

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Explanation:

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How do you divide $(n^4+5n^3-6n+3)div(n+3)$ using synthetic division?