How do you divide and rationalize the denominator for $2/(sqrt3+sqrt2)$ ?

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How do you divide and rationalize the denominator for $2/(sqrt3+sqrt2)$ ?

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Answer 1 · 2015-04-01T18:40:47

You can multiply and divide by $sqrt(3)-sqrt(2)$ to get:
$2/(sqrt(3)+sqrt(2))×(sqrt(3)-sqrt(2))/(sqrt(3)-sqrt(2))=(2sqrt(3)-2sqrt(2))/(3-2)=$
$=2sqrt(3)-2sqrt(2)$

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How do you divide and rationalize the denominator for $2/(sqrt3+sqrt2)$ ?

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How do you divide and rationalize the denominator for 2/(sqrt3+sqrt2)2/(sqrt3+sqrt2)?

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How do you divide and rationalize the denominator for $2/(sqrt3+sqrt2)$ ?