How do you divide (6-10i) / (7-2i) ?

1 Answer
George C.
Dec 18, 2015

Multiply both numerator and denominator by the Complex conjugate of the denominator and simplify to find:

(6-10i)/(7-2i) =62/53-58/53i

Explanation:

(6-10i)/(7-2i)

=((6-10i)(7+2i))/((7-2i)(7+2i))

=((6)(7)+(6)(2i)+(-10i)(7)+(-10i)(2i))/(7^2+2^2)

=(42+12i-70i+20)/(49+4)

=(62-58i)/53

=62/53-58/53i

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