How do you divide $(4 n^{2} + 7 n - 5) \div (n + 3)$ $(4n^2+7n-5)div(n+3)$ and identify any restrictions on the variable?

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How do you divide $(4 n^{2} + 7 n - 5) \div (n + 3)$ $(4n^2+7n-5)div(n+3)$ and identify any restrictions on the variable?

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Answer 1 · 2017-11-01T13:41:36

$4 n - 5 + \frac{10}{n + 3}$ $4n-5+10/(n+3)$

Explanation:

$one way is to use the divisor as a factor in the numerator$ $"one way is to use the divisor as a factor in the numerator"$

$consider the numerator$ $"consider the numerator"$

$4 n (n + 3) - 12 n + 7 n - 5$ $color(red)(4n)(n+3)color(magenta)(-12n)+7n-5$

$= 4 n (n + 3) - 5 (n + 3) + 15 - 5$ $=color(red)(4n)(n+3)color(red)(-5)(n+3)color(magenta)(+15)-5$

$= 4 n (n + 3) - 5 (n + 3) + 10$ $=color(red)(4n)(n+3)color(red)(-5)(n+3)+10$

$quotient = 4 n - 5, remainder = 10$ $"quotient "=color(red)(4n-5)," remainder "=10$

$\Rightarrow \frac{4 n^{2} + 7 n - 5}{n + 3} = 4 n - 5 + \frac{10}{n + 3}$ $rArr(4n^2+7n-5)/(n+3)=4n-5+10/(n+3)$

$with restriction n \neq - 3$ $"with restriction "n!=-3$

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How do you divide $(4 n^{2} + 7 n - 5) \div (n + 3)$ $(4n^2+7n-5)div(n+3)$ and identify any restrictions on the variable?

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Explanation:

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How do you divide (4n2+7n−5)÷(n+3)(4n^2+7n-5)div(n+3) and identify any restrictions on the variable?

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How do you divide $(4 n^{2} + 7 n - 5) \div (n + 3)$ $(4n^2+7n-5)div(n+3)$ and identify any restrictions on the variable?