How do you divide #(3sqrt(2x^6y))/(5 sqrt(8x^5 y^6))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Joe D. Apr 3, 2015 #(3sqrt(2x^6y))/(5sqrt(8x^5y^6))# #= 3/5 * sqrt((2x^6y)/(8x^5y^6))# #= 3/5 * sqrt(1/4 * xy^(-5))# #= 3/5 * sqrt((1/2)^2 * xy^(-5))# #=3/5*1/2*sqrt(xy^(-5))# #=3/10sqrt(xy^(-5))# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1560 views around the world You can reuse this answer Creative Commons License