How do you divide 3/(-i)? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Rory K. Sep 15, 2016 3i Explanation: 3/-i x (-i)/-i = (-3i)/(-i)^2 (-3i)/i^2 = 3i ....since ([sqrt(-1)]^2 = -1 Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient (-5+i)/(-7+i)? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of 12/(5i)? How do I rationalize the denominator of a complex quotient? How do I divide 6(cos^circ 60+i\ sin60^circ) by 3(cos^circ 90+i\ sin90^circ)? How do you write (-2i) / (4-2i) in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 1570 views around the world You can reuse this answer Creative Commons License