How do you divide #(-3-9i)/(5-8i)#?

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How do you divide #(-3-9i)/(5-8i)#?

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Answer 1 · 2016-10-17T14:45:38

The answer is #57/89-(69i)/89#

Explanation:

You must multiply numerator and denominator by the conjugate of thedenominator
#(-3-9i)/(5-8i)=((-3-9i)*(5+8i))/((5-8i)(5+8i))=(-15-24i-45i-72i^2)/(25-64i^2)#
as #i^2=-1#
The result is #(-15+72-69i)/(25+64)=(57-69i)/(89)=57/89-(69i)/89#

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How do you divide #(-3-9i)/(5-8i)#?

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