How do you divide $(2 x^{3} + 9 x^{2} + 2 x - 21) \div (x + 3)$ $(2x^3+9x^2+2x-21)div(x+3)$ using synthetic division?

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How do you divide $(2 x^{3} + 9 x^{2} + 2 x - 21) \div (x + 3)$ $(2x^3+9x^2+2x-21)div(x+3)$ using synthetic division?

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Answer 1 · 2016-11-15T15:53:13

The quotient is $= (2 x^{2} + 3 x - 7)$ $=(2x^2+3x-7)$

Explanation:

Let's do the long division

$a a a a$ $color(white)(aaaa)$ $2 x^{3} + 9 x^{2} + 2 x - 21$ $2x^3+9x^2+2x-21$ $a a a a$ $color(white)(aaaa)$ $∣$ $∣$ $x + 3$ $x+3$

$a a a a$ $color(white)(aaaa)$ $2 x^{3} + 6 x^{2}$ $2x^3+6x^2$ $a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $∣$ $2 x^{2} + 3 x - 7$ $2x^2+3x-7$

$a a a a a a$ $color(white)(aaaaaa)$ $0 + 3 x^{2} + 2 x$ $0+3x^2+2x$

$a a a a a a a a$ $color(white)(aaaaaaaa)$ $+ 3 x^{2} + 9 x$ $+3x^2+9x$

$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $0 - 7 x - 21$ $0-7x-21$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $- 7 x - 21$ $-7x-21$

$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $- 0 - 0$ $-0-0$

The quotient is $= (2 x^{2} + 3 x - 7)$ $=(2x^2+3x-7)$

no remainder

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How do you divide $(2 x^{3} + 9 x^{2} + 2 x - 21) \div (x + 3)$ $(2x^3+9x^2+2x-21)div(x+3)$ using synthetic division?

1 Answer

Explanation:

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How do you divide (2x3+9x2+2x−21)÷(x+3)(2x^3+9x^2+2x-21)div(x+3) using synthetic division?

1 Answer

Explanation:

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How do you divide $(2 x^{3} + 9 x^{2} + 2 x - 21) \div (x + 3)$ $(2x^3+9x^2+2x-21)div(x+3)$ using synthetic division?