How do you divide $(2n^3+62n-26n^2+4)div(2n-6)$ using synthetic division?

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How do you divide $(2n^3+62n-26n^2+4)div(2n-6)$ using synthetic division?

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Answer 1 · 2017-06-11T09:39:24

The remainder is $=269$ and the quotient is $=n^2+34n+89$

Explanation:

Let's perform the synthetic division

$color(white)(aaaa)$ $3$ $color(white)(aaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaaa)$ $31$ $color(white)(aaaaaa)$ $-13$ $color(white)(aaaaa)$ $2$
$color(white)(aaaaaaaaaaaa)$ _________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $color(white)(aaaaaaa)$ $3$ $color(white)(aaaaaaa)$ $102$ $color(white)(aaaa)$ $267$
$color(white)(aaaaaaaaaaaa)$ ________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaaa)$ $34$ $color(white)(aaaaaaa)$ $89$ $color(white)(aaaa)$ $color(red)(269)$

The remainder is $=269$ and the quotient is $=n^2+34n+89$

$(n^3+31n^2-13n+2)/(n-3)=n^2+34n+89+269/(n-3)$

N.B The numerator and denominator were divided by the common factor $2$

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How do you divide $(2n^3+62n-26n^2+4)div(2n-6)$ using synthetic division?

1 Answer

Explanation:

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Science

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Humanities

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How do you divide (2n^3+62n-26n^2+4)div(2n-6)(2n^3+62n-26n^2+4)div(2n-6) using synthetic division?

1 Answer

Explanation:

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How do you divide $(2n^3+62n-26n^2+4)div(2n-6)$ using synthetic division?