How do you divide $(2k^3-13k^2-77k+60)div(k-10)$ using synthetic division?

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Answer 1 · 2018-03-06T20:07:38

Quotient is $2k^2+7k-7$ and remainder is $-10$

$2k^3-13k^2-77k+60$

= $2k^3-20k^2+7k^2-70k-7k+70-10$

= $2k^2*(k-10)+7k*(k-10)-7*(k-10)-10$

= $(2k^2+7k-7)*(k-10)-10$

Hence quotient is $2k^2+7k-7$ and remainder is $-10$

How do you divide (2k^3-13k^2-77k+60)div(k-10)(2k^3-13k^2-77k+60)div(k-10) using synthetic division?