How do you divide # (2-7i)/(2-8i) # in trigonometric form?

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Answer 1 · 2016-01-19T02:26:53

Find the polar form #C_p = (R, theta)#
given #C = x +iy#
Then the polar form is #R = sqrt(x^2+y^2)#
And #theta= tan^-1 (y/x)#

Thus #R_1= sqrt(53); theta_1= tan^-1(7/2); #

careful on the angle use the sign of the imaginary number to get it right (hint it is in the 4th quadrant...

#R_2= sqrt(68); theta_2 = tan^-1(8/2); #

again make sure you have the right angle.

now divide #R = R_1/R_2# and the angle is simply the difference of #theta = theta_1 - theta_2#

Good luck, hope it helped
Yonas