How do you divide $\frac{12}{\sqrt{7} + 2}$ $12/(sqrt7+2)$ ?

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How do you divide $\frac{12}{\sqrt{7} + 2}$ $12/(sqrt7+2)$ ?

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Answer 1 · 2015-06-04T15:07:14

First I`ll try to get rid of the square rrot on the denominator:
$\frac{12}{\sqrt{7} + 2} \cdot \frac{\sqrt{7} - 2}{\sqrt{7} - 2} = \frac{12 (\sqrt{7} - 2)}{7 - 4} = \frac{12 (\sqrt{7} - 2)}{3} = 4 (\sqrt{7} - 2)$ $12/(sqrt(7)+2)*(sqrt(7)-2)/(sqrt(7)-2)=(12(sqrt(7)-2))/(7-4)=(12(sqrt(7)-2))/3=4(sqrt(7)-2)$

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How do you divide $\frac{12}{\sqrt{7} + 2}$ $12/(sqrt7+2)$ ?

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How do you divide $\frac{12}{\sqrt{7} + 2}$ $12/(sqrt7+2)$ ?