How do you differentiate $y=x^2(sin^-1x)^3$ ?

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Answer 1 · 2018-05-03T01:19:06

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$y=x^2((sinx)^(-1))^3$

$(dy)/(dx)=x^2*3((sinx)^(-1))^2*1/sqrt(1-x^2)+2x*((sinx)^(-1))^3$

$(dy)/(dx)=(3x^2((sinx)^(-1))^2)/sqrt(1-x^2)+2x((sinx)^(-1))^3$

How do you differentiate y=x^2(sin^-1x)^3y=x^2(sin^-1x)^3?