How do you differentiate #y=x^2(sin^-1x)^3#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Lucy May 3, 2018 Below Explanation: #y=x^2((sinx)^(-1))^3# #(dy)/(dx)=x^2*3((sinx)^(-1))^2*1/sqrt(1-x^2)+2x*((sinx)^(-1))^3# #(dy)/(dx)=(3x^2((sinx)^(-1))^2)/sqrt(1-x^2)+2x((sinx)^(-1))^3# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 3349 views around the world You can reuse this answer Creative Commons License