How do you differentiate y=sin^-1(2x)?
1 Answer
Feb 11, 2017
Explanation:
differentiate using the
color(blue)"chain rule"
color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx[sin^-1(f(x))]=1/(sqrt(1-(f(x))^2)).f'(x))color(white)(2/2)|)))
y=sin^-1(2x)
rArrdy/dx=1/(sqrt(1-(2x)^2)).d/dx(2x)
color(white)(rArrdy/dx)=2/(sqrt(1-4x^2))
