How do you differentiate #y = cos^-1 (e^-t)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Joel Kindiak Aug 29, 2015 Differentiate implicitly. Explanation: #y=cos^-1 (e^(–t))# #cos y = e^(–t)# Differentiating wrt #t#: #–sin y dy/dt = –e^(–t)# #–sqrt(1-cos^2 y) dy/dt = –e^(–t)# #–sqrt(1-e^(–2t)) dy/dt = –e^(–t)# #dy/dt = e^(–t) / sqrt(1-e^(–2t))# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 5008 views around the world You can reuse this answer Creative Commons License