How do you differentiate #y=arcsin(x^2)#?

1 Answer
Jim G.
Jan 29, 2017

#dy/dx=(2x)/(sqrt(1-x^4))#

Explanation:

differentiate using the #color(blue)"chain rule"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(d/dx(arcsin(f(x)))=1/(sqrt(1-f(x)^2)).f'(x))color(white)(2/2)|)))#

#y=arcsin(x^2)#

#rArrdy/dx=1/(sqrt(1-(x^2)^2)).d/dx(x^2)#

#=(2x)/(sqrt(1-x^4))#

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