How do you differentiate y=arcsec(1/x)? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer bp Jun 2, 2015 y= arc sec (1/x)= arc cos x dy/dx = -1/sqrt(1-x^2) Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 4106 views around the world You can reuse this answer Creative Commons License