How do you differentiate #y = 10^(1-x^2)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer Eddie Jun 24, 2016 # y' = -2x * ln(10) * 10^(1-x^2)# Explanation: #y = 10^(1-x^2)# #ln y = (1-x^2)ln(10)# #1/y \ y' = -2x * ln(10)# # y' = -2x * ln(10) * 10^(1-x^2)# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 1709 views around the world You can reuse this answer Creative Commons License