How do you differentiate the following parametric equation: # x(t)=t-(t+1)e^t, y(t)= t^2-e^(t-1) #? Calculus Parametric Functions Derivative of Parametric Functions 1 Answer Jim S Nov 16, 2017 Solution: #x'(t)=1-te^t-2e^t# , #y'(t)=2t-e^(t-1)# Explanation: #x'(t)=(t)'-(t+1)'e^t-(t+1)(e^t)'# = #1-e^t-(t+1)e^t# #=1-e^t-te^t-e^t= 1-te^t-2e^t# #y'(t)=2t-e^(t-1)(t-1)'# = #2t-e^(t-1)# Answer link Related questions How do you find the second derivative of a parametric function? How do you find derivatives of parametric functions? How do you find #dy/dx# for the curve #x=t*sin(t)#, #y=t^2+2# ? How do you find the equation of the tangent to the curve #x=t^4+1#, #y=t^3+t# at the point... How do you find #(d^2y)/(dx^2)# for the curve #x=4+t^2#, #y=t^2+t^3# ? How do you find parametric equations of a tangent line? How do you find parametric equations for the tangent line to the curve with the given parametric... How do you find the equation of a line tangent to the curve at point #t=-1# given the parametric... How do you differentiate the following parametric equation: # x(t)=t^3-5t, y(t)=(t-3) #? How do you differentiate the following parametric equation: # x(t)=lnt, y(t)=(t-3) #? See all questions in Derivative of Parametric Functions Impact of this question 1533 views around the world You can reuse this answer Creative Commons License