How do you differentiate the following parametric equation: $x (t) = ln t - t, y (t) = t {cos}^{2} t$ $x(t)=lnt-t, y(t)= tcos^2t$ ?

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Answer 1 · 2018-04-04T04:11:21

Find the derivative of the $x$ $x$ and $y$ $y$ equations.

$x'(t) = 1/t - 1$
$y'(t) = 1(cos^2t) - tsintcost = cos^2t - tsintcost$

Therefore

$dy/dx = (cos^2t - 2tsintcost)/((1 -t)/t)$

$dy/dx= (tcos^2t - 2t^2sintcost)/(1 - t)$

Hopefully this helps!

How do you differentiate the following parametric equation: x(t)=lnt-t, y(t)= tcos^2t x(t)=lnt−t,y(t)=tcos2t x(t)=lnt-t, y(t)= tcos^2t ?