How do you differentiate #sin(xyz) = x + 2y + 8z#? Calculus Basic Differentiation Rules Implicit Differentiation 1 Answer Cesareo R. May 31, 2016 Be more specific. Explanation: The relationship #sin(x y z)=x-2y-8z# defines a surface as can be seen. (Figure attached). A surface admits quite a large number of differentiation types. Be more specific. Answer link Related questions What is implicit differentiation? How do you find the derivative using implicit differentiation? How do you find the second derivative by implicit differentiation? How do you find #y''# by implicit differentiation of #x^3+y^3=1# ? How does implicit differentiation work? How do you use implicit differentiation to find #(d^2y)/dx^2# of #x^3+y^3=1# ? How do you Use implicit differentiation to find the equation of the tangent line to the curve... How do you use implicit differentiation to find #y'# for #sin(xy) = 1#? How do you find the second derivative by implicit differentiation on #x^3y^3=8# ? What is the derivative of #x=y^2#? See all questions in Implicit Differentiation Impact of this question 1785 views around the world You can reuse this answer Creative Commons License