How do you differentiate #sin(x^2)(cos(x^2))#? Calculus Basic Differentiation Rules Product Rule 1 Answer Massimiliano Apr 29, 2015 In this way, with the chain rule and the product rule: #y'=cosx^2*2x*cosx^2+sinx^2*(-sinx^2)*2x=# #=2x(cos^2x-sinx^2)#. Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1464 views around the world You can reuse this answer Creative Commons License