How do you differentiate #g(y) =(x^2 + 6)(x^2 - 1) # using the product rule?

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How do you differentiate #g(y) =(x^2 + 6)(x^2 - 1) # using the product rule?

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Answer 1 · 2016-01-06T15:56:37

#2x(2x^2 +5)#

Explanation:

The product rule states that if #h(x) = f(x)g(x)# then #h'(x)= f'(x)g(x) + f(x)g'(x)#
#:. d/dxg(y) =( d/dx(x^2+6))(x^2-1) + (x^2+6)d/dx(x^2-1) #
#= 2x(x^2-1) +(x^2+6)*2x#
#=2x^3 -2x +2x^3 +12x#
#=4x^3 +10x#
#=2x(2x^2 +5)#

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How do you differentiate #g(y) =(x^2 + 6)(x^2 - 1) # using the product rule?

1 Answer

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