How do you differentiate #g(y) =(x^2 + 3)(x^3 + 4) # using the product rule? Calculus Basic Differentiation Rules Product Rule 1 Answer Sonnhard Jun 6, 2018 #g'(x)=2x(x^3+4)+(x^2+3)*3x^2# Explanation: After the product rule #(uv)'=u'v+uv'# we get #g'(x)=2x(x^3+4)+(x^2+3)*3x^2# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1395 views around the world You can reuse this answer Creative Commons License