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How do you differentiate #g(y) = (x^2 - 1) (4x^6 + 5) # using the product rule?

1 Answer

Dec 18, 2015

#g'(x) = 2x(4x^6 + 5) + 24x^5(x^2 - 1)#

Explanation:

#g# is the product of two functions #u# & #v# with #u(x) = x^2 - 1# & #v(x) = 4x^6 + 5#

So the derivative of #g# is #u'v + uv'# with #u'(x) = 2x# & #v'(x) = 24x^5#.

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