How do you differentiate # g(x) =sin^2(x/6) #?

1 Answer
Shwetank Mauria
Mar 31, 2016

#(dg)/(dx)=1/6sin(x/3)#

Explanation:

To differentiate #g(x)=sin^2(x/6)#, we use the concept of function of function, as #g(x)=(f(x))^2# where #f(x)=sin(x/6)#.

Hence, #(dg)/(dx)=(dg)/(df)*(df)/(dx)#

= #2sin(x/6)*cos(x/6)*1/6#

= #1/6sin(x/3)# (using formula #sin2x=2sinxcosx#)

Related questions
See all questions in Special Limits Involving sin(x), x, and tan(x)
Impact of this question
2487 views around the world
You can reuse this answer
Creative Commons License