Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you differentiate #f(x)=xarctansqrtx#?

1 Answer

Apr 4, 2018

#=>arctan(sqrtx) + sqrt(x)/(2(1+x))#

Explanation:

#f(x) = x arctan (sqrtx)#

#f'(x) = (d(x))/(dx) arctan(sqrtx) + x (d(arctan(sqrtx)))/(dx)#

#= arctan(sqrtx) + x(1/(1+(sqrtx)^2))(d(sqrtx))/(dx)#

#= arctan(sqrtx) + x/(1+x)*1/(2sqrtx)#

#= arctan(sqrtx) + sqrt(x)/(2(1+x))#

Related questions

See all questions in Differentiating Inverse Trigonometric Functions

Impact of this question

1327 views around the world

You can reuse this answer
Creative Commons License