How do you differentiate #f(x) = ln (1/e)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Other Bases 1 Answer Jim H Mar 27, 2015 #ln(1/e)=ln(e^(-1)=-1# So #f(x)=ln(1/e)=-1# #f'(x)=0# Answer link Related questions How do I find #f'(x)# for #f(x)=5^x# ? How do I find #f'(x)# for #f(x)=3^-x# ? How do I find #f'(x)# for #f(x)=x^2*10^(2x)# ? How do I find #f'(x)# for #f(x)=4^sqrt(x)# ? What is the derivative of #f(x)=b^x# ? What is the derivative of 10^x? How do you find the derivative of #x^(2x)#? How do you find the derivative of #f(x)=pi^cosx#? How do you find the derivative of #y=(sinx)^(x^3)#? How do you find the derivative of #y=ln(1+e^(2x))#? See all questions in Differentiating Exponential Functions with Other Bases Impact of this question 1703 views around the world You can reuse this answer Creative Commons License