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How do you differentiate # f(x) = arctan(1/(1+x^2)) #?

1 Answer

Mar 10, 2016

#f'(x) = 1/(1+(1/(1+x^2))^2 ) *-(2x)/(1+x^2)^2#

Explanation:

#f'(u)=1/(1+u^2) * u'#
#f'(x) = 1/(1+(1/(1+x^2))^2 ) *-1/(1+x^2)^2 (2x)#
#f'(x) = 1/(1+(1/(1+x^2))^2 ) -(2x)/(1+x^2)^2#

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