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How do you differentiate #f(x)=(5e^x+tanx)(x^2-2x)# using the product rule?

1 Answer

Apr 25, 2018

#f'(x)=(5e^x+sec^2x)(x^2-2x)+(5e^x+tanx)(2x-2)#

Explanation:

For #f(x)=(5e^x+tanx)(x^2-2x)#, we find #f'(x)# by doing:

#f'(x)=d/dx[5e^x+tanx] (x^2-2x)+(5e^x+tanx)d/dx[x^2-2x]#

#f'(x)=(5e^x+sec^2x)(x^2-2x)+(5e^x+tanx)(2x-2)#

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