How do you determine whether $triangle ABC$ has no, one, or two solutions given $A=60^circ, a=15, b=24$ ?

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Answer 1 · 2018-02-18T13:13:52

No solution.

$hatA = 60^@, a = 15, b = 24$

$a / sin A = b / sin B = c / sin C$

$sin B = (b sin A) / a = (24 * sin 60) / 15 = 1.3856$

Since $sin B$ cannot have more than value 1, $Delta ABC$ has no solution.

How do you determine whether triangle ABCtriangle ABC has no, one, or two solutions given A=60^circ, a=15, b=24A=60^circ, a=15, b=24?