How do you determine whether the pair (1,0) is a solution to #y<x^3-4x^2+2#?

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Answer 1 · 2016-12-06T15:04:39

As the statement is not true then (1,0) is not a solution

Given:#" "(x,y)->(1,0)#

Substitute the values and if the resulting statement is true then (1,0) is a solution.

Consider the right hand side (RHS)

#x^3-4x^2+2" "->" "(1)^3-4(1)^2+2 = -1#

The ordered pair (1,0) needs to satisfy

#LHS < RHS" "->" "0<-1 color(red)(" "larr" False")#

As the statement is false then (1,0) is not a solution