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How do you determine whether # f(x) = (x^2+8)^2# is an odd or even function?

1 Answer

Nov 20, 2015

#f(-x) = ((-x)^2+8)^2 = (x^2+8)^2 = f(x)#

So #f(x)# is an even function.

Explanation:

An even function is one that satisfies #f(-x) = f(x)# for all #x#

An odd function is one that satisfies #f(-x) = -f(x)# for all #x#

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