How do you determine the total mass of an original 28.0-milligram sample of Po-210 that remains unchanged after 414 days?

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How do you determine the total mass of an original 28.0-milligram sample of Po-210 that remains unchanged after 414 days?

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Answer 1 · 2017-06-12T05:38:48

Given the 138.4 day half-life of the radioisotope $3.5 \cdot m g$ $3.5*mg$ of $^{210} P o$ $""^210Po$ will remain.

Explanation:

Given the boundary conditions of the problem it was SPECIFIED that the mass of $^{210} P o$ $""^210Po$ remained unchanged. I acknowledge, however, that this is a radioactive decay problem, and $^{210} P o$ $""^210Po$ is a screaming hot isotope and $α - emitter$ $alpha-"emitter"$ with a half-life of 138.4 days; these data SHOULD have been supplied with the problem.

And so your polonium isotope has experienced 3 half-lives.........And there is thus ${(\frac{1}{2})}^{3} = \frac{1}{8}$ $(1/2)^3=1/8$ of the original mass, i.e. $3.5 \cdot m g$ $3.5*mg$ .

Note that I think this was the first radioisotope isolated by Marie Curie who named it after her native Poland.

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How do you determine the total mass of an original 28.0-milligram sample of Po-210 that remains unchanged after 414 days?

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