How do you determine the quadrant in which the angle -132^circ50' lies?

1 Answer
Nov 29, 2017

−132^@50' is in the 3^(rd) quadrant

Explanation:

If we consider the conventional unit circle, an angle theta is measured counter-clockwise from the positive x-axis through the four quadrants delimited by 90^@, 180^@,270^@,360^@ respectively. These detemine the 1^(st), 2^(nd), 3^(rd) and 4^(th) quadrants.

However, we can also measure negative angle theta clockwise from the positive x-axis where the four quadrants are delimited by -90^@, -180^@,-270^@,-360^@ as -theta passes through the 4^(th), 3^(rd), 2^(nd) and 1^(st) quadrants around the circle.

Here we are asked in which quadrant theta = −132^@50'

−132^@50' is between -90^@ and -180^@ and hence it is in the 3^(rd) quadrant.

An altenative approach would be to consider:

−132^@50' = 360^@ −132^@50' =227^@10'

Since 227^@10' is betwen 180^@ and 270^@ i.e the 3^(rd) quadrant

-> −132^@50' is in the 3^(rd) quadrant.