How do you determine the quadrant in which $\frac{11 π}{8}$ $(11pi)/8$ lies?

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How do you determine the quadrant in which $\frac{11 π}{8}$ $(11pi)/8$ lies?

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Answer 1 · 2017-10-18T14:22:13

Quadrant 3

Explanation:

$\frac{11 π}{8} = \frac{3 π}{8} + π$ $(11pi)/8 = (3pi)/8 + pi$
On the unit circle, the arc (or angle) $\frac{3 π}{8}$ $(3pi)/8$ is located in Quadrant 1, therefor, the arc $(\frac{3 π}{8} + π)$ $((3pi)/8 + pi)$ is located in Quadrant 3.

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How do you determine the quadrant in which $\frac{11 π}{8}$ $(11pi)/8$ lies?

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How do you determine the quadrant in which $\frac{11 π}{8}$ $(11pi)/8$ lies?