How do you determine the linear function whose graph is a line that contains the points (-1, -8) and (2, 10)?

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Answer 1 · 2016-07-16T04:12:21

#6x-y-2=0#

The linear function whose graph is a line that contains the points #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)#.

Hence equation of line passing through #(-1,-8)# and #(2,10)# is

#(y-(-8))/(10-(-8))=(x-(-1))/(2-(-1))# or

#(y+8)/(10+8)=(x+1)/(2÷1)# or

#(y+8)/18=(x+1)/3# or

#3(y+8)=18(x+1)# or

#y+8=6(x+1)# or

#y+8=6x+6# or #6x-y-2=0#