How do you determine if # y=-x^3# is an even or odd function?
1 Answer
Apr 10, 2016
y is odd.
Explanation:
y(x) is even or odd according as
Here, #y(-x)=-(-x)^3=-(-x^3)=x^3=-y(x).
So, y is an odd function of x.
The graph of an odd function will be symmetrical about the origin.
If (x, y) is a point on the graph. its mirror image with respect to the origin (# -x, -y) will be on the graph.
