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How do you determine if #f(x) =sin(2x)# is an even or odd function?

1 Answer

Shwetank Mauria

Jul 24, 2016

#f(x)=sin(2x)# is an odd function.

Explanation:

A function #f(x)# is even if #f(-x)=f(x)# and it is odd if #f(-x)=-f(x)#

Here #f(x)=sin(2x)#

and #f(-x)=sin(2xx(-x))-sin(-2x)=-sin(2x)=-f(x)#

Hence, #f(x)=sin(2x)# is an odd function.

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