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How do you determine if #f(x) = sec x# is an even or odd function?

1 Answer

Shwetank Mauria

Sep 30, 2016

#f(x)=secx# is an even function

Explanation:

A function #f(x)# is even if #f(-x)=f(x)#

and #f(x)# is odd if #f(-x)=-f(x)#

Here we have #f(x)=secx# and

#f-(x)=sec(-x)=secx=f(x)#

Hence #f(x)=secx# is an even function

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