How do you determine if #f(x) - 2 cos x# is an even or odd function?

1 Answer
Feb 13, 2017

See explanation.

Explanation:

To check if a function is odd or even you have to calculate #f(-x)#.

The function is:

  • Even if #f(-x)=f(x)#

  • Odd if #f(-x)=-f(x)#

If we check the given function we get:

#f(-x)=-2cos(-x)=-2cosx#

From this calculatiobs we see that #f(-x)=f(x)#, so the given function is even.