How do you determine if $f (x) = 1 - X^{\frac{1}{3}}$ $f(x)= 1 - X^(1/3)$ is an even or odd function?

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How do you determine if $f (x) = 1 - X^{\frac{1}{3}}$ $f(x)= 1 - X^(1/3)$ is an even or odd function?

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Answer 1 · 2016-06-20T14:31:12

odd function

Explanation:

FIRST YOU NEED TO KNOW :
1.EVEN FUNCTION $f (x) = f (- x)$ $f(x)=f(-x)$ these type of function symmetry to y-axis
2.ODD FUNCTION $f (x) = - f (- x)$ $f(x)=-f(-x)$ these type of function symmetry to $O (0, 0)$ $O(0,0)$

$f (- x) = 1 - {(- x)}^{\frac{1}{3}}$ $f(-x)=1-(-x)^(1/3)$
$f (x) = 1 - x^{\frac{1}{3}}$ $f(x)=1-x^(1/3)$

because

$f (x) \neq f (- x)$ $f(x)!=f(-x)$

so it is odd function

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How do you determine if $f (x) = 1 - X^{\frac{1}{3}}$ $f(x)= 1 - X^(1/3)$ is an even or odd function?

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