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How do you determine if #2sin(x)cos(x)tan^2(x)# is an even or odd function?

1 Answer

A. S. Adikesavan

Apr 14, 2016

Odd

Explanation:

Change x to #-x# in f(x).

If #f(-x)=-f(x)#, the function is odd.
If #f(-x)=f(x)#, the function is even.

#sin(-x)=-sin x, cos(-x)=cos x and tan(-x)=-tan x. Also, (-1)^2=1#

Here, #f(-x)=-f(x)#. So, the given function is odd. .

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