How do you determine conjugate acid and base pairs?

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How do you determine conjugate acid and base pairs?

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Answer 1 · 2016-08-11T10:56:00

See this [old answer.](https://socratic.org/questions/what-is-the-conjugate-for-benzoic-acid-hc7h5o2)

Explanation:

The conjugate base of any acid $H A$ $HA$ simply the acid MINUS a proton, $H^{+}$ $H^+$ ; when we do this for $H A$ $HA$ we get $A^{-}$ $A^-$ . Likewise the conjugate acid of any base $A^{-}$ $A^-$ is simply the base plus a proton, $H^{+}$ $H^+$ , to give $H A$ $HA$ . Mass and charge are conserved.

To use sulfuric acid as an example, we start with the $H_{2} S O_{4}$ $H_2SO_4$ formula; less a proton, this gives $H S O_{4}^{-}$ $HSO_4^-$ as the conjugate base, and the conjugate base of $bisulfate$ $"bisulfate"$ is $sulfate$ $"sulfate"$ ion, $S O_{4}^{2 -}$ $SO_4^(2-)$ . All I am doing is exchanging protons, $H^{+}$ $H^+$ , and conserving mass and charge.

Can you tell the conjugate bases of the following acids: $H C l O_{4}$ $HClO_4$ ; $H_{3} P O_{4}$ $H_3PO_4$ ; $N H_{4}^{+}$ $NH_4^+$ ; $N H_{3}$ $NH_3$ ; $N H_{2}^{-}$ $NH_2^-$ ; $H C \equiv C H$ $HC-=CH$ ; $N H^{2 -}$ $NH^(2-)$ ?

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How do you determine conjugate acid and base pairs?

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