How do you describe the end behavior of #y=-x^6+x^4-5x^2+4#?
1 Answer
Dec 7, 2016
See explanation and graph.
Explanation:
At x = 0, y'=0 and y''< 0. So, y(0) = 4 is the maximum y.
graph{y+x^6-x^4+5x^2-4=0x^2 [-10, 10, -5, 5]}