How do you describe the end behavior for #f(x)=-x^3+3x^2-4#?

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Answer 1 · 2016-12-19T02:10:23

See explanatiion

#y= -x^3(1-3/x+4/x^3) to -oo#, as #x to oo and#

#y to oo#, as #x to -oo#

#y'=-3x(x-2) = 0#, when x = 0 and 2

#y''=-6(x-1) =0 at x =1, >0 at x =0 and <0 a tx = 2#

Local min y = y(0) = -4, max y = y(x) = 0 and (1, -2) is the point of

inflexion.

graph{-x^3+3x^2-4 [-10, 10, -5, 5]}