How do you convert z=i1cos(π3)+isin(π3) in polar form?

1 Answer
Jun 4, 2017

Given: z=i1cos(π3)+isin(π3)

We know that 1cos(π3)=2

z=2+i+isin(π3)

We know that sin(π3)=32

z=2+i(1+32)

r= (2)2+(1+32)2

r2.7

The angle is in the second quadrant:

θ=π+tan1(1234)

θ2.39

z=2.7ei2.39