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How do you convert #y = x^2 # to polar form?

1 Answer

Jun 23, 2016

#r = tan theta sec theta#

Explanation:

#x = r cos theta#
#y = r sin theta#

#r sin theta = (r cos theta)^2 = r^2 cos^2 theta#

#sin theta = r cos^2 theta#

#r = (sin theta)/(cos^2 theta) = tan theta sec theta#

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