How do you convert #x^2 -4y^2 =4# to polar form?

1 Answer
Jim G.
Jul 8, 2016

#r^2=4/(cos^2theta-4sin^2theta)#

Explanation:

To convert from #color(blue)"Cartesian to Polar form"#

#color(orange)"Reminder"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta,y=rsintheta)color(white)(a/a)|)))#

#rArrx^2-4y^2=4rArr(rcostheta)^2-4(rsintheta)^2=4#

#rArrr^2cos^2theta-4r^2sin^2theta=4#

#rArrr^2(cos^2theta-4sin^2theta)=4rArrr^2=4/(cos^2theta-4sin^2theta)#

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